Sol. Cos=0.6=610=35=basehypo.
Using Pythagoras Theorem, we get
AC2=AB2+BC2
52=AB2+32
25=AB2+9
AB2=25-9
AB2=16
AB=4
Sin=perp.Hypo.=45, Tan=perp.Base=43
Substituting the values in the given expression,
(5Sin-3Tan)=0
545-3454-4=0=R.H.S
If Cos theta=0.6. Show that (5Sin theta-3Tan theta)=0