Solution: If a number x is chosen from the numbers 1,2,3 and a number y is selected from the numbers 1,4,9 then possible outcomes of the experiment are (1,1), (1,4), (1,9), (2,1), (2,4), (2,9), (3,1), (3,4), (3,9).

So the number of possible outcomes = 3 x 3 = 9

Let A be the event of getting xy<9, then the outcomes favourable to A are

(1,1), (1,4), (2,1), (2,4), (3,1).

Therefore, Number of favourable outcomes = 5

Hence, P(A) = Number of favourable outcomes/Total number of outcomes = 5/9.

**Try to solve these Question also in comment section:**

Q1. If the nth term of an AP is (5n-2), find the (i) first term, (ii) common difference and (iii) 19th term.

Ans: (i) 3, (ii) 5, (iii)93.

Q2. if the pth, qth and rth terms of an AP be a,b,c respectively, then show that a(q-r)+b(r-p)+c(p-q)=0.