## Find the value of 1/a+b+x = 1/a+1/b+1/x

Solution: 1/a+b+x = 1/a+1+b+1+x

=> 1/a+b+x – 1/x= 1/a+1+b

=> x-(a+b+x)/(a+b+x)(x) = b+a/ab

=> x-a-b-x/(a+b+x)(x) = b+a/ab

=> -(a+b)/(a+b+x)(x) = b+a/ab

=> -1/(a+b+x)(x) = 1/ab

=> -ab = x(a+b+c)

=> ax + bx + x^2 + ab = 0

=> x^2 + ax + bx + ab = 0

=> (x+b)(x+a) = 0

=> x = -a, x = -b

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