## cos squared theta minus sin square theta equal to 1 minus 10 squared theta by 1 + 10 squared theta prove the identity

Cos^2-Sin^2=1-Tan^2/1+Tan^2

Taking RHS, 1-Tan^2/1+Tan^2 ………..(i)

We Know that, Tan=SinCos, by putting in eq (i), we get

1-(Sin/Cos)^2/1+(SinCos)^2

1-(Sin^2/Cos^2/1+(Sin^2-Cos^2)

Cos2-Sin2Cos2Cos2+Sin2Cos2

Cos2-Sin2Cos2+Sin2

Cos2-Sin21

Cos2-Sin2=LHS

So, RHS=LHS

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