Find the value of 1/a+b+x = 1/a+1/b+1/x
Solution: 1/a+b+x = 1/a+1+b+1+x
=> 1/a+b+x – 1/x= 1/a+1+b
=> x-(a+b+x)/(a+b+x)(x) = b+a/ab
=> x-a-b-x/(a+b+x)(x) = b+a/ab
=> -(a+b)/(a+b+x)(x) = b+a/ab
=> -1/(a+b+x)(x) = 1/ab
=> -ab = x(a+b+c)
=> ax + bx + x^2 + ab = 0
=> x^2 + ax + bx + ab = 0
=> (x+b)(x+a) = 0
=> x = -a, x = -b
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